Question

18
A man starts from rest and after l0 seconds its velocity becomes 36 km/h What is the value of its acceleration?​

Answer 1

Explanation:

Initial velocity (u) =0 km/h

Final velocity ( V) = 36 km/h

Time taken (t) = 10 sec

= 10/60×60 h

= 1/360 h

Acceleration (a) =V - u/t

= 36 - 0/1/360

= 36 ×360

= 12960 km/ h^2

Answer 2

ANSWER:

• Acceleration = 1m/s^2

GIVEN:

• Initial velocity = 0 m/s
• Final velocity = 36 km/hr
• Time = 10 sec

TO FIND:

• Acceleration (a)

SOLUTION:

Firstly we have to change 36km/hr not m/s.

$= 36 \times \frac{1000}{3600} \\ = 36 \times \frac{5}{18} \\ = 10ms {}^{ - 1}$

Formula

$\implies \: a = \frac{v - u}{t}$

Putting all the values we get;

$\implies \: a = \frac{10 - 0}{10} \\ \implies \: a = 1ms {}^{ - 2}$

NOTE:

some important formulas

$\implies \: a \: = \frac{v - u}{t} \\ \implies \: s = ut + \frac{1}{2} at {}^{2} \\ \implies \: v {}^{2} - u {}^{2} = 2as$