Question

18. A particle of mass 2 kg is moving along 'AB'
according to y = x - 4 with speed 4 m/s, then
angular momentum about 'O' is
B
or.
lly
Its
(0) 16/2 kg m/s
(3) 32 kg m/s
(2) 32.2 kgm/s
(4) 16 kg m/s​

Answer 1

Solution:

We have to find out:

$\bullet$ Perpendicular distance from O to P.

$\bullet$ Angular momentum of particle P about origin O.

Given:

$\bullet$ Equation of line y = x - 4

$\bullet$ y = (1)x - 4

Hence:

Slope of line , m = 1 = tanα

So: α = 45°

Here:

$\implies$ OP (r) = 4cos45° = 2√2

Then:

$\boxed{\sf{Angular\:momentum = mvr}}$

$\implies$ 2kg × 4 m/s × 2√2

$\implies$ 16√2 kg m/s

Note: Check this attachment!

Answer 2

Answer:

Solution:

We have to find out:

. perpendicular distance from o to p

. angular momentum of particular p about origin O.

Given:

. equation of line y= x - 4

.y=(1) x - 4

Hence:

slope of line, m = 1= tana

So: a = 45°

Here:

= op (r) = 4cos45°= 2√2

Then:

(Angular momentum = mvr)

=2kg×4 m/s ×2√2

=16√2 kg m/s

Explanation:

Note : check this attachment!