Question

(18) a, ß, y are the zeros of the polynomial f(x) = ax^3 + bx^2+ cx + d, then 1/a+1/B+1/Y is

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Answer 1

Step-by-step explanation:

A+B+Y= - b/a

AB+BY+YA=c/a

ABY= - d/a

1/A+1/B+1/Y= BY+AY+AB/ABY

= c/a*-a/d

=c/d

Answer 2

Answer:

c/-d

Step-by-step explanation:

ax^3+bx^2+cx+d

zeroes:A,B,Y

A+B+Y=-b/a

A*B*Y=-d/a

AB+BY+YA=c/a

So,

1/A+1/B+1/Y= (AB+BY+AY)/A*B*Y

=(c/a)/(-d/a)

=c/-d