Question

= 18 abe.
5. If a + 2b + 3c = 0, show that a³ + 8b²+ 27 C³=18 abc
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Answer 1

Answer:

a3+8b3+27c3=18abc.

Step-by-step explanation:

a+2b+3c=0.

(a+2b+3c)3=(0)3.

(a)3+(2b)3+(3c)3+3(a)(2b)(3c)=0.

a3+8b3+27c3-18abc=0.

a3+8b3+27c3=18abc.

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