Question

18
Calculate the molarity of 6,3 g of oxalic acid (H,C,0,2,0) present in 500 ml of solution.
(Molecular weight of oxalic acid is 120).
a 0.1
b) 0.2
c) 0.4
d) 1.0
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Answer 1

Answer:

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Explanation:

Molar mass of Oxalic acid (H2C2O4.2H2O)=126

Molarity=Volume of the solution in mL(Molar massMass of solute in grams)×1000

Molarity=100(12612.6)×1000

Molarity=1 M