Question

18 cattles graze a field in 12 days.6 cattles can graze such of 3 fields in x day. What is x ?

Answer 1

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18 cattles graze a field in 12 days.6 cattles can graze such of 3 fields in x day. What is x

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So, the “speed” of one cow is “1/45 th part of the field in 13 days”. Or, more universally “(1/45)/13 part of the field in one day”. That is 1/585.

Si, if we have 9 days for the same field, how many cow do we need? We divide the number of “the fields” by “the speed of one cow” and have the quantity of cows for “one-day job”. That’s “1 field divided by (1/585) fields-by-cow-per-day”. That is “585 cows” (for one day).

But we’re not in a hurry, we have 9 days and can go 9 times slower. We’ll need 9 times less of the cows quantity. So, that’s “585/9” and that’s 65 cows for 1 field and 9 days.

Answer 2

18 cattrls in 12 Days

6 cattles in 4 Days..