Question

18.
Construct APQR, if QP = QR, angleP = 36°
[Hint: Calculate measure of angle
Q and the construct]​

Answer 1

Answer:in Δ pqr

pq = pr

=> Triangle is isosceles

=> ∠ p = ∠r

∠ p + ∠q +  ∠r = 180°  (sum of angles of triangle)

∠q = 40° given

=>  ∠ p + 40°+  ∠r = 180°

=>  ∠ p +  ∠r = 140°

∠ p = ∠r

=> ∠ p +  ∠p = 140°

=> 2∠p = 140°

=> ∠p = 70°

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