Question

18
dilgie
d) re
5.
If(x+1) is factor of x2+3mx+6 then find the value ofm.​

Answer 1

Answer:

applied quadractic equation formula

b^2-4ac

d= b^2-4ac

x^2+3mx+6=0

a = 1 ,b = 3m,c =6

d=(3m)^2-4*1*6

d= 9m^2-24=0

9m^2=24

m^2= 24/9

m=✓24/9