18. Find acceleration and Tension in the string 500N 10Kg 20Kg
Answers
Answered by
0
Answer:
If a be the acceleration of the system, (10+20)a=500 or a=
3
50
m/s
2
Tension in the string, T=10a=10×
3
50
=
3
500
N
Explanation:
Answered by
1
Answer:
500/3 N
Explanation:
If a be the acceleration of the system,
(10+20)a=500 or a= 50/3 m/s^2
Tension in the string,
T= 10a = 10× 50/3
= 500/3 N
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