18. Find the area of the shaded portion in the gives
d by
figure.
nced
re is
are
36 m
4 m
m is
with
ter of
4 m
24 m
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Answer:
For the triangle having the sides 122m, 120m and 22m :
s=2122+120+22=132m
Area of triangle =s(s−a)(s−b)(s−c)
=132(132−122)(132−120)(132−22)
=132×10×12×110=1320m2
For the triangle having the sides 22m, 24m and 26m :
s=222+24+26=36m
=36(36−22)(36−24)(36−26)
=36×14×12×10=24105
=24×10.25m2(approx.)=246m2
There, the area of the shaded portion
=(1320−246)m2=1074 m2
Step-by-step explanation:
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