18.Find the compound interest on ₹ 8000 for 2 months at 20% per annum
compounded Yearly
Answers
Answered by
1
Step-by-step explanation:
2 months of a year
2/12 = 1/6 = 0.6
A = P (1+r/100)n
= 8000 (1 + 20/100)⁰.⁶
= 8000 ( 1+0.2)⁰.⁶
= 8000(1.2)⁰.⁶
= 8000 × 0.144
= 1152
Answered by
3
Step-by-step explanation:
2 moths of year
2/12 = 1/6 = 0.6
A. P = { 1 +r/100} n
= 8000 = { 1 + 20/100} 0. 6
= 8000 { 1 +0.2} 0.6
= 8000 {1.2} 0.6
8000 x 0.144
= 1152
I hope it may help to you..
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