Question

18. Find the equation of the straight line passing through the point (4.-3) and perpendicular to the line passing through the points (1.1) and (2,3).​

Answer 1

Slope of line whose two points are given is  

m=2−13−1=2

This is Perpendicular to required line  

So, Slope of required line is 2−1

Hence, Equation is y−(−3)=2−1(x−4)⇒2y+6=−x+4⇒x+2y+2=0

mark me as brainlent

Answer 2

Step-by-step explanation:

just take a line on the point where these value are located as (3,-3) (1,1) (2,3)