Question

18. Find the product of complex numbers (2 +9i), (11 + 3i).​

Answer 1

Answer:

Step-by-step explanation:

2x-3y=-1 3x+5y=5

2x-3y=-1   en1 *5

3x+5y=5  en2 *3

10x-15y=-5  en3

6x+15y=15 en4

  add en3 +en4

        10x-15y=-5  en3

  +     6x+15y=15 en4

         16x      = -15

       x  16-15 =1

       x=1

      put x= 1  in en 1

         2x-3y=-1

         2[1]-3y=-1

         2-3y=-1

          -3y=2-1=1

          y=-3-1

         y=4

Answer 2

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