Question

18. Find the ratio of maximum wavelength of lyman series and minimum wave length of paschen series​

Answer 1

Answer:

λ

1

=R(

n

1

2

1

−

n

2

2

1

)

Lymen series: n

1

=1

Shortest wavelength, n

2

=∞

λ

1

=R(

1

2

1

)=R

Largest wavelength: n

2

=2

λ

1

=R(

1

2

1

−

2

2

1

)=

4

3R

Ratio =

4

3