Math, asked by shampasharmin786, 3 months ago

18. Find the smallest angle in a triangle whose sides are of
length 3x, 4x and 6x.


Answers

Answered by singharshnoor28
3

Step-by-step explanation:

side 1=3x

side 2=4x

side 3= 6x

angle sum property of ∆

6x+4x+3x=180

13x=180

x=13.84 approx

hence smallest angel will be 3x :)

pls pls mark as brainliast ༎ຶ‿༎ຶ

Answered by WaizaSuha
0

Step-by-step explanation:

Solution:

=> In this question we will use angle sum property:

GIVEN :- Size of three angles of a triangle are 3x ,5 x ,4x .

Find :- The smallest Angel of the triangle .

Solution :

- Angle 1 = 3x .

Angle 2 = 5x.

Angle 3 = 4x.

Angle sum property of a triangle

=> 180 °

Angle 1 + Angle 2 + Angle 3

=> 180 °

3x + 5x + 4x

=> 180° .

12x => 180 °.

x=> {180°}{12}

12

180°

x=> 15

CalculationofAngles:

Angle 1 => 3x × 15°.

Answer => 45°.

Angle 2=> 5x × 15°.

Answer=> 75°.

Angle 3=> 4x × 15° .

Answer=> 60°.

SmallestAngle:

Answer => 45° .

Hence , we get the answer .

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