Question

18. For what value of a , - 3 is a zero of the polynomial p(x) = x3 + 12x2+ax+60​

Answer 1

Answer:

a=47

Step-by-step explanation:

as we are given that -3 is the zero of p(x), we will let the value of p(x) be 0

substituting x=-3 in given p(x)=$x^{3}+ 12x^{2} +ax+60$

$=-3^{3}+12(-3)^{2}+-3a+60=0\\ \\= -27+108-3a+60=0\\\\=141-3a=0\\\\=-3a=-141\\\\=a=47$

hope its clear

mark me brainliest

Answer 2

Pls mark as brainliest answer