Question

18) From the sum of 4x² + 3xy and -x? - xy +z?, subtract the sum of 3x2 - y² and x? +
xy + 2y?​

Answer 1

Step-by-step explanation:

In the given equation, real parts of both LHS and RHS will be equal

 Therefore, 4x2+3xy=4y2−2x2⟹9x2+6xy−8y2=09x2+12xy−6xy−8y2=03x(3x+4y)−2y(3x+4y)=0(3x+4y)(3x−2y)=0…(1)

Similarly, imaginary parts are equal

2xy−3x2=3xy−2y2⟹3x2+xy−2y2=03x2+3xy−2xy−2y2=03x(x+y)−2y(x+y)=0(x+y)(3x−2y)=0…(2)

From (1) and (2) 

3x=2y