Question

18 g of glucose is dissolved in 1 kg of water in a saucepan

Answer 1

Answer:

373.202 K

Explanation:

Moles of glucose= 18 g /180 g mol -1 =0.1mol

No of kilograms of solvent =1 kg

Thus molality of glucose solution = 0.1mol kg -1

For water , change in boiling point

ATb = Kb * m = 0.52 K kg mol -1 * 0.1 mol kg-1= 0.052 K

Since water boils at 373.15 K at 1.013 bar pressure , therefore,the boiling point of solution will be 373.15 + 0.052 = 373.202 K.