Question

18 Garv tested the solubility of four substances A, B, C and D at different temperatures and collected the following data. (Solubility refers to the amount of solute in grams dissolved in 100g of water to give a saturated solution) Substance dissolved Temperature in Kelvin 290K 313K 323K 343K 353K Solubility X 22, 34, 40, 93 ,109 Y 43, 43, 43, 50 ,50 Z 27 ,30 ,34, 37 ,40 T 25, 38, 42, 54 ,64 i) Which salt has the lowest solubility at 323K? ii) A student prepared a saturated solution of X at 323K and then added 25g water to it. What mass of X must be added to again make the solution saturated? iii) The solubility of which salt is least affected by increase in temperature? iv) What mass of T would be required to make 200g of saturated solution at 290K?​

Answer 1

Answer:

(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need 10062×50=31 g of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because g.

(ii)  Solubility of sodium chloride at 293 K is 36 g.

(iii) Solubility of Potassium chloride at 293 K is 35 g.

(iv) Solubility of Ammonium chloride at 293 K is 37 g.                                                      

The solubility of Ammonium chloride is highest at this temperature.

(d)The solubility of salt increases with the increase

Explanation:

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