Chemistry, asked by Tanyachouhan3435, 9 months ago

18. Given the following reactions involving, A, B, C and D: (i) C + B +  C + + B (ii) A + D  No reaction (iii) C + + A  No reaction (iv) D + B + +  D + + B The correct arrangement of A, B, C, D in order of their decreasing ability as reducing agent. (1) D > B > C > A (2) A > C > D > B (3) C > A > B > D (4) C > A > D > B

Answers

Answered by nidaeamann
17

Answer:

Hence the order will be

C>A>D>B ...............Option 4

Explanation:

Considering all four equations one by one.

In equation (1), reaction shows that the redox activity of element C is more than that of element B. So from this reaction, the order of activity is C>B  

In equation (2), reaction shows that the redox activity of element A is more than that of element D. So from this reaction, the order of activity is A>D  

In equation (3), reaction shows that the redox activity of element C is more than that of element A. So from this reaction, the order of activity is C>A  

In equation (4), reaction shows that the redox activity of element D is more than that of element B. So from this reaction, the order of activity is D>B  

Hence the order will be

C>A>D>B

Similar questions