Question

18 gm glucose (c6h12o6) is dissolved in water to prepare 200 ml solution (i) % v/v of solution (ii) strength in g/l (iii) molarity​

Answer 1

Given molarity of the solution =0.2

Volume of solution =200ml=0.2 L

Molarity=

Volume in litres

Moles of solute

Moles of solute =0.2×0.2=0.04

No. of moles=

Molar mass

Given mass

Molar mass of C

6

H

12

O

6

=6×12+12+6×16=180g

Mass of glucose in the solution = 180×0.04=7.2g

Answer 2

Answer:

Given molarity of the solution =0.2

Volume of solution =200ml=0.2 L

Moles of solute =0.2×0.2=0.04

Molar mass of C 6H12O⁶=6×12+12+6×16=180g

Mass of glucose in the solution = 180×0.04=7.2g