Question

18 gram glucose is dissolved in 100 gram H2O calculate freezing point of the solution​

Answer 1

Answer:

∆Tf=kf×molality here ∆Tf= freezing point depression (Tsolvent-Tsolution) and kf is molal freezing point depression constant and it's value for water is 1.86°c/m and molality = no.of mole of solute ×1000/weight of solvent ,,, ∆Tf = 1.86×18×1000/180×100 after solving it ∆Tf is 1.86°c and then ∆Tf =T solvent- T solution we know that T solvent means water freezing point is 0°c then 1.86=0-Tsolution ,,, T solution= -1.86°c ans