Question

18 gram jal mein upasthit jal anuon ki sankhya kya hogi​

Answer 1

Answer:

6.02*10^23 molecules

Explanation:

1 mole of H2O = (1*2+16) = 18 grams of H2O

= 6.02*10^23 molecules of H2O

Answer 2

Explanation:

18 18 gram jal mein upsthit jal ki sankhya gyat karte bataiye

18 gram jal mein upsthit chal ki sankhya gyat karke bataiye