Question

18 gram of glucose is dissolved in 90 gram of water then the relative lowering of vapour pressure of solution is​

Answer 1

Answer:

Molecular mass of water= 2×1+1×16=18g

=2×1+1×16=18g

For 90g178.2g water n  

A

​  

=5

Molecular mass of glucose  6×12+12×1+6×16=180g

For 18g glucose n  

B

​  

=0.1

Now,  X  

B

​  

=  

0.1+5

0.1

​  

=0.0196 ~0.02