18 guests have to be seated half on each side of a long table. 4 particular guests desire to sit on one particular side and 3 others on the other side .Find the number of arrangements is?
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9p4*9p3*11!*2
4 guests one side out of 9 seats =9p4
3 guests another side out of 9 seats =9p3
remain 11 guest can sit in 11 seats any where =11!
the 3 and 4 perticular guest can change their side =2
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