18.
How can you distinguish the compounds CH3-C=O-C2H5 and C2H5-C=O-C2H5 by simple
chemical test?
Answers
Answer:
by IODOFORM test.. .
Explanation:
the first compound will give the IODOFORM test because of the presence of CH3 group attached with C=O and will give colour. I don't exactly remember wht colour it is , right now...
the second compound will not give IODOFORM test.. as CH3 is not present which is a pre requisite for iodoform test.
Do, read about this test once on internet or this is given in 12th chemistry NCERT volume 2 , chapter 3 of volume 2.
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CH₃-CO-C₂H₅ is distinguished by the Iodoform test.
We know that compounds having the keto-methyl group(R-CO-CH₃) responds positive to the Iodoform test.
Amongst the two given compounds, if we look closely, we can see that in CH₃-CO-C₂H₅, the keto-methyl group is present whereas in C₂H₅-CO-C₂H₅, this group is absent.
When compounds having this keto methyl group is reacted with I₂ in the presence of NaOH or KOH, an yellow solid having the smell of iodex, iodoform (CHI₃) is produced.
So, in this way CH₃-CO-C₂H₅ responds to the iodorm test by producing iodoform.
CH₃-CO-C₂H₅ + I₂ + NaOH → C₂H₅-CO-O⁻Na⁺ + CHI₃