Question

18.How much momentum will a dump-bell of mass 10 kg transfer to the floor if it falls from a height.of 80 cm ? Take its downward acceleration to be 10 m s-2​

Answer 1

Answer:

Explanation:

Known Terms:

u = Initial speed

v = Final speed

a = Acceleration

m = Mass

s = Distance.

45

Given:

Mass of the dummbell, m = 10 kg

Distance attain by the dummbell, s = 80 cm = 0.8 m

Acceleration in the downward direction, a = 10 m/s²

Initial velocity of the dummbell, u = 0

(Because dummbell starts from rest.)

To Calculate:

1. Final velocity of the dummbell (v) 2. Momentum of dummbell.

Formula to be used:

v² = u²+2 as

p = m v

Solution:

Putting all the values, we get

v² = u²+2 as

v² = 0 +2 (10) 0.8

v² = 16

v = 4 m/s

Momentum, p=mv

= 10x4

= 40 kg m/s

Hence, the momentum with which the dummbell hits the floor 40 kg m/s.