Question

18. If 42 = 64,91 = 81 , 23 = 36 then 80 = ?
81
83
1
0​

Answer 1

The answer would be 0, since if you were to opposite that and apply the rule you've stated it, then the final answer would be 0.

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Answer 2

If 42 = 64 , 91 = 81 , 23 = 36 then 80 = 0

Given :

42 = 64 , 91 = 81 , 23 = 36

To find :

The value of 80 =

• 81

• 83

• 1

• 0

Solution :

Step 1 of 3 :

Write down the given data

Here it is given that

42 = 64 , 91 = 81 , 23 = 36

Step 2 of 3 :

Find the pattern

$\displaystyle \sf{42 = {(4 \times 2)}^{2} = {8}^{2} = 64 }$

$\displaystyle \sf{91 = {(9 \times 1)}^{2} = {9}^{2} = 81 }$

$\displaystyle \sf{23 = {(2\times 3)}^{2} = {6}^{2} = 36 }$

Thus we get

$\displaystyle \sf{ab = {(a \times b)}^{2} }$

Step 3 of 3 :

Find the value of 80

For the number 80 we get

$\displaystyle \sf{80 = {(8 \times 0)}^{2} = {0}^{2} = 0 }$

Thus we can conclude that ,

If 42 = 64 , 91 = 81 , 23 = 36 then 80 = 0

Hence the correct option is 0

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