Question

18. If A and B are arbitrary square matrices of same order, then:
(a) (AB)' - AB
(b) (ABY - BA
(C) (A)(B') - B'A' (d) (A + BY-A-B​

Answer 1

Answer:

If A and B are square matrices of the same order such that A B = B A, then proveby induction that A B^n=B^n A. Further, prove that (A B)^n=A^n B^nfor all n in N.