18. If a+b+c=4-4 then
a3+3+C3=?
O 3a2bc2
O
-2
O 3abc
ОО
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2
Answer:
3abc
Step-by-step explanation:
As we know that,
a³+b³+c³-3abc = (a+b+c)(a²+b²+c²-ab-bc-ca)
If (a+b+c) = 0 then,
0 × (a²+b²+c²-ab-bc-ca)
= 0 [anything multiplied with 0 is always 0]
Given that (a+b+c) = 4-4 = 0
So, a³+b³+c³-3abc = 0
or, a³+b³+c³ = 3abc.
Hope it helps you...
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