18. If a + b + c = 66 and ab + bc + ca = 1071 where a, b, and c are all prime numbers, find the value of
abc.
b) 2876
c) 1886
d) 1765
Answers
Answered by
11
Answer:
If you carefully look at the first equation, you will find that sum of three primes is even. As the only even prime number is 2, one of them has to be 2.
Let A=2
Then, B+C=64
Now, putting the value of A in the second equation,
2B+BC+2C=1071
2(C+B) + BC =1071
We know that C+B=64
128+BC=1071
BC=1071–128 =943
We want ABC
ABC=2*BC
=2*943=1886
If A+B+C=66 and AB+BC+CA=1071, and A, B, C are prime numbers, then ABC=1886.
Answered by
0
Answer:
the value is 1886
Step-by-step explanation:
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