Question

18. If a + b + c = 66 and ab + bc + ca = 1071 where a, b, and c are all prime numbers, find the value of
abc.
b) 2876
c) 1886
d) 1765​

Answer 1

Answer:

If you carefully look at the first equation, you will find that sum of three primes is even.  As the only even prime number is 2, one of them has to be 2.

Let A=2

Then, B+C=64

Now, putting the value of A in the second equation,

2B+BC+2C=1071  

2(C+B) + BC =1071  

We know that C+B=64  

128+BC=1071  

BC=1071–128   =943  

We want ABC  

ABC=2*BC  

=2*943=1886  

If A+B+C=66 and AB+BC+CA=1071, and A, B, C are prime numbers, then ABC=1886.

Answer 2

Answer:

the value is 1886

Step-by-step explanation:

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