Question

18. If ΔABC ~ ΔDEF, AB = 4cm, DE = 6cm, EF = 9cm and FD = 12cm, find the perimeter of ΔABC.​

Answer 1

Step-by-step explanation:

In Similar Triangles the sides are proportional, so here,

$\frac{AB}{DE} = \frac{BC}{EF} = \frac{AC}{DF} \\ \\ \frac{4}{6} = \frac{BC}{9} = \frac{AC}{12}$

With the above by cross multiplying, we get,

BC = 6 cm and AC = 8 cm...

Perimeter of ∆ABC = AB + BC + AC

=> 4 cm + 6 cm + 8 cm

=> 18 cm

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