18. If one zero of the polynomial p(x) = (t2+ 1)x2 + 4x + 2t be reciprocal of
the other then t equals.
(b) -1
(c) +1
(d) NOTA
(a) 1
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Option - (c) : +1
Let one of the two zeroes be x then the other one will be 1/x
p(x) = (t² + 1)x² + 4x + 2t
☛ Product of zeroes = ( constant term ) / (coefficient of x² )
☛ x × 1/x = (2t) / (t² + 1)
☛ 1 = 2t / (t² + 1)
☛ t² + 1 = 2t
☛ t² - 2t + 1 = 0
☛ t² - t - t + 1 = 0
☛ t(t - 1) - 1(t - 1) = 0
☛ (t - 1)(t - 1) = 0
t - 1 = 0
==> t = 1
Hence, The value of t is 1
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