18. If the diagonals of the Rhombus are in the ratio 4:7 and the area is 504sqcm. Find the
length of the diagonals.
Answers
Answer:
Step-by-step explanation:
Diagonals are 24 cm and 42 cm.
Step-by-step explanation:
Given :
Diagonals of the rhombus are in the ratio 4 : 7 and the area is 504 cm²
To find :
Length of the diagonals.
Solution :
We know,
Area\;of\;rhombus\;= \frac{Diagonal_1*Diagonal_2}{2}Areaofrhombus=
2
Diagonal
1
∗Diagonal
2
Let the diagonals be,
4x and 7x
We have,
Area = 504 cm²
Substituting,
504\;=\;\frac{4x*7x}{2}504=
2
4x∗7x
504\;=\frac{28x^2}{2}504=
2
28x
2
Cross multiply,
1008\;=\;28x^21008=28x
2
x^2\;=\;\frac{1008}{28}x
2
=
28
1008
x^2\;=36x
2
=36
x = \sqrt{36}x=
36
x = 6x=6
Diagonals are,
4x = 24 cm
7x = 42 cm
Step-by-step explanation:
Let the ratios of diagonal be x then,
(4x*7x)/2 = 504
(28xsq)/2= 504
14xsq = 504
x = sq root of (504/14)
x=sq root of 36
x=6
4x=24
7x=42
hence, the diagonal of the Rhombus are 24cm and 42cm