Question

18. If the HCF of 210 and 55 is expressible in the form of 210 x 5 + 55 A, then find the value
of [2-A].
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Answer 1

Answer:

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Step-by-step explanation:

Since now the remainder is zero, therefore divisor at this stage, that is 5, is the HCF of 210 and 55. Comparing equation with the given equation:5=210×5+55y, we get, y=−19. This is the required solution.