Question

18. If the reaction, 2A + 3D -
products, is first-order in A and
second-order in D, then the rate law
will be
O k[A] [D]2
O k[A]2 [D]
Ok [A]2 [D]2
O k[A] [D]
​

Answer 1

Answer:

your answer is D

k[A] [D]

Answer 2

The rate law will be written as $(4)K[A][D]^{2}$.

Given,

Order with respect to A=1

Order with respect to B=2.

To find,

the rate law expression.

Solution:

Order of a reaction is the sum of the power of the reactant species in the rate law expression. It is an experimental quantity. It can be a fraction or an integar. It's maximum value is 3.

Order of a reaction is written according to the below format,

Rate of reaction = $K[A]^{p} [B]^{q}$

$n=p+q$

where,

K-rate constant

p-order of reaction with respect to reactant A

q-order of reaction with respect to reactant B

n-order of reaction.

So the rate law expression of this reaction will be,

Rate law=$K[A][D]^{2}$

here,

n=1+2

n=3.

The order of this reaction is 3.

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