Math, asked by saarazaki, 1 year ago

18. If the side of a square is increased by 30%, its
area is increased by
(a) 29 %
(b) 30 %
(c) 69 %
(d) None​


hkhatodiya2003: 69 peecent

Answers

Answered by Iamkeetarp
52

A = a^2

when a is increased by 30 %

a' = a + 0.3a = 1.3a

new area = (a')^2

new area = (1.3)^2 a^2

new area = 1.69 *a^2

new area % = 169%

new area increasement = 69%

69% hope it helped you.......


saarazaki: there is no option of 60%
Iamkeetarp: option d
saarazaki: no its wrong
Iamkeetarp: How
saarazaki: its answer is 69 but idk the solution
Iamkeetarp: ohh
arvind8140: nive
aditya8363y: hii
Answered by abhi569
71

Answer:

Correct option is ( c ).

Step-by-step explanation:

Let the length of side of square be a units.

From the properties of square :

  • Area of square = ( length of side )^2

Thus,

= > Original area of the square = ( length of it's side )^2

= > Original area of the square = ( a unit )^2

= > Original area of the square a^2 unit^2

If side of square is increased by 30% :

= > New length of side of square = a unit + 30% of a unit

= > New length of side of square = a{ 1 + ( 30 / 100 ) unit

= > New length of side of square = a x ( 130 / 100 ) = 13a / 10 unit

Now,

= > New area of square = ( 13a / 10 unit )^2

= > New area of square = 169a / 100 unit^2

Thus,

= > Area is increased by = { 169a^2 / 100 }{ a^2 } x 100 %

= > Area is increased by = 169%

Hence,

Increase in area = 169% - 100% = 69%

Hence the required option is ( c ).


abhi569: Otherwise the thing which you want to get : new area - original area = 169% - 100% = 69% . This is increase in area
saarazaki: thnkew ❣️
abhi569: welcome
YugangRana: option c is the right
YugangRana: 30% increase its means that 3/10. initial 10 final 10+3=13 . so initial area= 100 final area = 169 increase 69 initial 100 then 6900/100 = 69%
Soumok: ur answer is just sparkling @bhaiya
abhi569: :-)
shapeofyou66: please answer my question
shapeofyou66: i am in trouble
abhi569: it has been answered,i think. If not,send the link in inbox,will answer on getting free
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