Question

18. If x = 12-1' y = 12 +1
find x2 + xy + y2​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

433

Step-by-step explanation:

$(x+y)^2=x^2+2xy+y^2\\\\\\where\\\\\\x = 12-1=11\\\\\\y=12+1=13\\\\\\(x+y)^2=x^2+2xy+y^2\\\\\\(11+13)^2=11^2+(2*11*13)+13^2\\\\\\therefore,\\\\\\x^2+xy+y^2=11^2+(11*13)+13^2\\\\\\x^2+xy+y^2=121+143+169\\\\\\x^2+xy+y^2=433$

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