18. In a reaction, 5.3 g of sodium carbonate react completely with 6 gram of acetic acid. The products were
a) Carbon dioxide = 2.2 g.
b) Water = 0.9 g.
c) Sodium acetate = 8.2 g
3
Calculate the amount of sodium carbonate and acetic acid to obtain 41 g sodium acetate.
Answers
Answer:
In the given reaction, sodium carbonate reacts with ethanoic acid to produce sodium ethanoate, carbon dioxide, and water
sodium carbonate + ethanoic acid → sodium ethanoate + carbon dioxide + water
We need to show that the law of conservation of mass is agreed in the above reaction.
Answer
let's first solve the reactant side
Mass of sodium carbonate=5.3g (given)
Mass of ethanoic acid=6g(given)
Now total mass before reaction that is mass of reactants = (5.3g + 6g) = 11.3g
now let's solve the product side
Mass of carbon dioxide = 2.2g (given)
Mass of water = 0.9g (given)
Mass of sodium ethanoate = 8.2g (given)
Now total mass after reaction that is mass of products = (8.2g + 2.2g + 0.9g) = 11.3g
Conclusion
Total mass before reaction=total mass after reaction
Therefore the given observation is in agreement with the law of conservation of mass.
Hope this helps...