Question

18.
In arrangement shown the block A of mass 15 kg is supported in equilibrium by the block B. Mass of
the block B is closest to
B
(A) 2 kg
(B) 3 kg
(C) 4 kg
(D) 5 kg
Please answer with explanation ​

Answer 1

Answer:

3 kg

Explanation:

Since blocks are at rest hence net force on each block is zero

by given daigram we can say that

T = mg

4T + T = 15g

T = 30 Newton

hence m = 3 kg

(B) 3kg

Hope it helps you...

Plz mark it as brainliest answer...