Question

18. In rectangle ABCD, diagonals BD and AC intersect at S. If AC= 40 and SD=(x+5), find the
value of x.
a) 10
b) 18
c) 15
d) 20

Answer 1

Step-by-step explanation:

AC =40

SD=(x+5)

x=?

40(x+5)

40x +200

240x

x= 240

Answer 2

Answer:

Step-by-step explanation:

As diagonals in a rectangle are equal

Hence, AC=BD

thus, half of AC and BD is also equal..

Hence, AS=SD ( S is the point of intersection of both the diagonals) (1)

Half of AC = 40/2=20

From (1)

AS=SD

20= x +5

x= 20-5

x = 15

Ans.