18 In the following figure, AB = EF, BC = DE
and angleB = angleE = 90°
Prove that AD = FC.
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Answer:
Step-by-step explanation:
Given that, BC=DE
⇒BC+CD=DE+CD (Adding CD on both sides)
⇒BD=CE ...(1)
Now, InΔABD and ΔEFC
AB=EF ...[Given]
∠ABD=∠FEC ...[Both =90
0
, perpendiculars]
BD=CE ...[From (1)]
⇒ABD≅ΔΔEFC ...[SAS congruence criterion]
⇒AD=FC ...[cpct]
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Answer:
where is the figure then how can I answer
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