Question

18 In the following figure, AB = EF, BC = DE
and angleB = angleE = 90°
Prove that AD = FC.
at​

Answer 1

Answer:

Step-by-step explanation:

Given that, BC=DE

⇒BC+CD=DE+CD    (Adding CD on both sides)

⇒BD=CE      ...(1)

Now, InΔABD and ΔEFC

AB=EF       ...[Given]

∠ABD=∠FEC      ...[Both =90  

0

, perpendiculars]

BD=CE       ...[From (1)]

⇒ABD≅ΔΔEFC     ...[SAS congruence criterion]

⇒AD=FC        ...[cpct]

Answer 2

Answer:

where is the figure then how can I answer