Question

18. In the given figure ABC is a triangle in which AD =
3CD and E lies on BD, DE = 2BE. What is the ratio
of area of triangle ABE and area of triangle ABC?
B
(a) 1/12
(c) 1/6
(b) 1/8
(d) 1/10

Answer 1

Answer:

I think answer is b 1/8 hope it's help you

Answer 2

Step-by-step explanation:

let the total area is 12 unit square then area of triangle ADB=9 and are of the triangle BDC=3 now coming to the triangle ADB, area of the triangle ABE= 3 and area of triangle ADE=6

so the ratio will be ∆ABE/∆ABC=3/12 = 1/4