Question

18. Initially the system is at rest. From the instance shown,
2m
*2m' is projected towards pulley with speed u. Find the
speed of 'm' just after the string becomes taut.
(A) 2u/3
(B) 4u/3
(C) u
(D) 5u/3​

Answer 1

Answer:

Speed u

Explanation:

Mass 2m moves forward without Acceleration at velocty u Till string is not Taut . It also means String gets Taut when falling Mass m gets a velocity u . Soon after string become Taut Mass has velocity u.