Question

18
Mathematical & Statistical Techniques -I (FY.B.Com.: SEM-1)
20. Ginny got 400 shares of market price of 180 per share. The total amount
she had to pay was 72,360. Find the rate of brokerage.​

Answer 1

Answer:

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.

Answer:ANSWER EXPLANATION: There are two ways to solve this question. The faster way is to multiply each side of the given equation by ax−2 (so you can get rid of the fraction). When you multiply each side by ax−2, you should have:24x2+25x−47=(−8x−3)(ax−2)−53You should then multiply (−8x−3) and (ax−2) using FOIL.24x2+25x−47=−8ax2−3ax+16x+6−53Then, reduce on the right side of the equation24x2+25x−47=−8ax2−3ax+16x−47Since the coefficients of the x2-term have to be equal on both sides of the equation, −8a=24, or a=−3.The other option which is longer and more tedious is to attempt to plug in all of the answer choices for a and see which answer choice makes both sides of the equation equal. Again, this is the longer option, and