18 men bind 900 books in 10 days. Find how many binders will be required
to bind 600 books in 12 days?
2 Draw a pie-chart for the following data of monthly expenditure of a family
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Answer:
Given: 18 binders bind 900 books in 10 days.
To find: Number of binders that will be required to bind 660 books in 12 days.
Formula : W_1M_2D_2=W_2M_1D_1W
1
M
2
D
2
=W
2
M
1
D
1
, where W = Work, M = Number of men, D= Days .
Put
\begin{gathered}W_1=900\ , M_1=18\ , D_1=10\\ W_2=660\ , D_2=12\end{gathered}
W
1
=900 ,M
1
=18 ,D
1
=10
W
2
=660 ,D
2
=12
we will find M_2M
2
\begin{gathered}(900)\times M_2\times (12)=(660)\times(18)\times(10)\\\\\Rightarrow\ M_2=\dfrac{(660)\times(18)\times(10)}{(900)\times12}=11\end{gathered}
(900)×M
2
×(12)=(660)×(18)×(10)
⇒ M
2
=
(900)×12
(660)×(18)×(10)
=11
Hence, 11 binders that will be required to bind 660 books in 12 days.
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