Question

18. O/N 10/P12/Q7, O/N 10/P11/Q11
The base for a statue rests on level ground. It is made from stone and is 2.0 m long, 2.5 m high
and 0.80 m wide. It has a weight of 96 000 N.
2.5 m
0.80 m) 2.0 m
What is the pressure that the base exerts on the ground?
в B 24 kPa
A 19 kPa
с 48 kPa
D 60 kPa​

Answer 1

Answer:-

• 60 kPa is the required answer .

Given:-

• Force acting ( F ) = 96000 N

• Length of statue ( l ) = 2 m

• Breadth of statue ( b ) = 0.80 m

• Height of statue ( h ) = 2.5 m

To Find:-

• Pressure exerted by base on the ground ( P )

Solution:-

According to the Question

Firstly we calculate the base area of the statue . Since ,the statue exerted pressure on the ground .

$:\implies$ Base Area of Staute = l × b

where,

• l denote length
• b denote breadth

Substitute the value we get

$:\implies$ Base area of statue = 2 × 0.80

$:\implies$ Base area of statue = 1.6m²

SO, the base area of the statue is 1.6m².

Now, finding the pressure exerted by statute on the ground .

Pressure is calculated by the force acting per unit area.

• P = F/A

where,

• P denote pressure exerted
• F denote Force
• A denote area

Substitute the value we get

$:\implies$ P = 96000/1.6

$:\implies$ P = 960000/16

$:\implies$ P = 60000 Pa

Now, changing the unit into KiloPascal by dividing with 1000 .

$:\implies$ P = 60000/1000

$:\implies$ P = 60kPa

• Hence, the required answer is 60kPa .

Correct Option is ( d ) 60kPa

Answer 2

Given :-

The base for a statue rests on level ground. It is made from stone and is 2.0 m long, 2.5 m high  and 0.80 m wide. It has a weight of 96000 N.

To Find :-

Pressure

Solution :-

At first we need to find area of base

Area of base = 2.0 × 0.80

Area of base = 1.6 m²

Now

P = F/A

P = 96000/1.6

P = 96000/16 × 10

P = 60000 Pa

We know that

1 kPa = 1000 Pa

6000 Pa = 60000/1000 = 60 kPa

[tex][/tex]