Math, asked by nirmalakumaribayi, 27 days ago

18. Once four students from class IX were selected for planation of flower plants in the school garden. The selected students are Pankaj, Raju, Deepak and Renu. As shown in the figure PQ and MN are parallel lines. Pankaj planted a sunflower plant at point P and Raju planted another sunflower plant at Q. Further Deepak planted Marigold at point M and
Renu planted Rose plant at N. There was a water pipeline XY which intersects PQ and MN at A and B and LXBN = 60 degree​

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Answers

Answered by purushothamanaji103
2

Answer:

i) answer is 120 degree because it is a linear pair which is 180 so its one side is 60 degree so we have to subtract 60 degree from 180 degree son the answer is 120 degree

Answered by RvChaudharY50
3

Solution :-

given that,

  • PQ || MN .
  • XY is a transversal .
  • ∠XBN = 60° .

so,

→ ∠z + ∠XBN = 180° (Angles on a straight line are supplementary.)

→ ∠z = 180° - 60°

→ ∠z = 120° (b) (Ans.)

now,

→ ∠x = ∠XBN (corresponding angles.)

→ ∠x = 60° (a) (Ans.)

and,

→ ∠p + ∠q = 180° (XB is a straight line , so angles are supplementary.) (c) (Ans.)

now,

→ Angle corresponding to ∠a = ∠q (d) (Ans.)

also,

→ (∠p + ∠q + ∠a + ∠z) / 6 = (180° + 180°)/6 = 360°/6 = 60° (a) (Ans.)

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