18. Our local club room is square in shape of side 15 m long, and 5 m high. There
are 4 doors in the club room each 1.5 m wide and 2 m high. Let's calculate the cost of
oil painting its 4 walls without doors at Rs. 350 per sq m.
Answers
Given that:
- Our local club room is square in shape of side 15 m long and 5 m high.
- There are 4 doors in the club room each 1.5 m wide and 2 m high.
To Find:
- The cost of oil painting its 4 walls without doors at Rs. 350 per sq m.
We know that:
- Area of walls = 2(L + B)H
Where,
- L = Length
- B = Breadth
- H = Height
We have:
Room is square in shape so,
- L = B = 15 m
- H = 5 m
Finding the area of four walls:
Area of four walls = 2(15 + 15)5
Area of four walls = 2 × 30 × 5
Area of four walls = 300
∴ Area of four walls = 300 m²
Finding the area of 4 doors:
Area of one door = 1.5 × 2
Area of 4 doors = 4 × 1.5 × 2
Area of 4 doors = 12
∴ Area of 4 doors = 12 m²
Finding the area for painting:
Area = Area of walls - Area of doors
- Area = 300 m² - 12 m²
- Area = 288 m²
Finding the cost of oil painting:
1 m² of painting cost = Rs 350
288 m² painting cost = Rs 350 × 288 = Rs 100800
Hence,
- The cost of oil painting its 4 walls without doors is Rs 100800.
Given :-
Our local club room is square in shape of side 15 m long, and 5 m high. There
are 4 doors in the club room each 1.5 m wide and 2 m high.
To Find :-
Calculate the cost of oil painting its 4 walls without doors at Rs. 350 per sq m.
Solution :-
We know that
Area of 4 walls = LSA of cuboid = 2(l + b)h
2(15 + 15)5
2(30)5
300 m²
Area of 4 doors = Area of one door × 4
Area of one door = 1.5 × 2
Area of one door = 3 m²
Now
Area of 4 doors = 3 × 4
Area of 4 doors = 12 m²
Now
Remaining area = 300 - 12
Remaining area = 288 m²
Cost = Rate × Area
Cost = 350 × 288 = 100800
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