18. Out of three numbers, the first is twice the second and is half of the third.
If the average of three numbers is 56, the difference of first and third
numbers is :
(S.S.C. 2005)
Answers
Answered by
1
Answer:
-16
Step-by-step explanation:
let the three numbers be a,b,c :
given: a=2b , a= c/2 => 2b= c/2
therefore, 4b= c
and, a+b+c= 56 (given)
2b+ b+ 4b= 56
7b= 56
b= 8
therefore, a= 2×8= 16 and c= 4×8 =32
hence, a-c= 16-32= -16
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