Math, asked by princerlsy, 11 months ago

18. Out of three numbers, the first is twice the second and is half of the third.
If the average of three numbers is 56, the difference of first and third
numbers is :
(S.S.C. 2005)​

Answers

Answered by ghoshpooja0203
1

Answer:

-16

Step-by-step explanation:

let the three numbers be a,b,c :

given: a=2b , a= c/2 => 2b= c/2

therefore, 4b= c

and, a+b+c= 56 (given)

2b+ b+ 4b= 56

7b= 56

b= 8

therefore, a= 2×8= 16 and c= 4×8 =32

hence, a-c= 16-32= -16

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